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प्रश्न
How will you convert ethyl chloride into n – butane?
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उत्तर
\[\ce{\underset{\text{}Ethyl chloride}{C2H5Cl + 2Na +}Cl - C2H5 ->[-2NaBr][dry ether] CH3 - \underset{\text{n - butane}}{CH2 - CH2 - CH3}}\]
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संबंधित प्रश्न
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{...........................}|\\
\ce{CH3 - C = CH2 + HBr->[Benzoyl][peroxide] H3C - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}
\end{array}\]
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