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प्रश्न
Read the following reaction and answer the questions given below:

- Write the name of the reaction.
- Identify the electrophile in it.
- How is this electrophile generated?
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उत्तर
- The name of the reaction is Friedel-Craft’s alkylation reaction.
- The electrophile in the reaction is +CH3.
- The electrophile +CH3 is generated as follows:
\[\ce{\underset{\text{Methyl chloride}}{CH3 -}Cl + AlCl3 -> \underset{\text{Electrophile}}{^+CH3 +}AlCl^-_4}\]
APPEARS IN
संबंधित प्रश्न
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is
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Read the following reaction and answer the questions given below.
\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{............................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide]CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}
\end{array}\]
- Write IUPAC name of the product.
- State the rule that governs formation of this product.
Read the following reaction and answer the questions given below.
\[\begin{array}{cc}
\phantom{..........................}\ce{CH3}\\\phantom{........................}|\\\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
|\phantom{......................................}\\
\ce{CH3}\phantom{....................................}\end{array}\]
- Write the IUPAC name of the product.
- State the rule that governs the formation of this product.
Identify ortho and para-directing groups from the following:
\[\ce{\underset{I}{–CHO},\underset{II}{–NHCOCH3},\underset{III}{–OCH3},\underset{IV}{–SO3H}}\]
