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प्रश्न
Identify giving reason whether the following compound is aromatic or not.

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उत्तर

The compound is aromatic since it has 6π electrons and hence, obeys the Huckel rule of aromaticity.
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संबंधित प्रश्न
Predict the possible product of the following reaction.
sulphonation of chlorobenzene
Identify giving reason whether the following compound is aromatic or not.

Identify giving reason whether the following compound is aromatic or not.

Read the following reaction and answer the questions given below:

- Write the name of the reaction.
- Identify the electrophile in it.
- How is this electrophile generated?
Consider the nitration of benzene using mixed con H2SO4 and HNO3 if a large quantity of KHSO4 is added to the mixture, the rate of nitration will be ______.
Which one of the following is non aromatic?
Some meta-directing substituents in aromatic substitution are given. Which one is most deactivating?
2 – butyne on chlorination gives ______.
Give IUPAC name for the following compound.
\[\ce{CH ≡ C – C ≡ C – C ≡ CH}\]
Describe the mechanism of Nitration of benzene.
Suggest a simple chemical test to distinguish propane and propene.
Write the chemical equations for combustion of propane.
How does Huckel rule help to decide the aromatic character of a compound?
Suggest the route for the preparation of the following from benzene.
3 – chloro nitrobenzene
What happens when ethylene is passed through cold dilute alkaline potassium permanganate.
Complete the following:
\[\begin{array}{cc}
\ce{CH2 - CH2 ->[Zn/C2H5OH]}\\
|\phantom{.......}|\phantom{..............}\\
\ce{Br}\phantom{.....}\ce{Br}\phantom{..............}
\end{array}\]
How will distinguish 1 – butyne and 2 – butyne?
When acetylene is passed through red hot iron tube at 873 K, ____________ is/are obtained as product/s.
Identify the hydrocarbon compound from following containing carbon atoms in the range of C6 to C8?
Direct bromination of benzene with excess reagent results in the formation of ____________.
The alkane formed on heating sodium butanoate with sodalime is ______.
Which of the following compounds on bromination yields
?
Conversion of hexane into benzene involves the reaction of ______.
Identify the X and Y in the following reactions.

Read the following reaction and answer the questions given below.
\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{...........................}|\\
\ce{CH3 - C = CH2 + HBr ->[Benzoyl][peroxide] H3C - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}
\end{array}\]
- Write the IUPAC name of the product.
- State the rule that governs the formation of this product.
Read the following reaction and answer the questions given below.
\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{...........................}|\\
\ce{CH3 - C = CH2 + HBr->[Benzoyl][peroxide] H3C - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}
\end{array}\]
- Write the IUPAC name of the product.
- State the rule that governs the formation of this product.
Read the following reaction and answer the questions given below.
\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{...........................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide]CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}\\
\end{array}\]
- Write the IUPAC name of the product.
- State the rule that governs the formation of this product.
Read the following reaction and answer the questions given below.
\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{............................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{..................................}
\end{array}\]
- Write IUPAC name of the product.
- State the rule that governs formation of this product.
Identify 'A' in the following reaction.
\[\ce{\underset{}{A + Chloromethane} ->[anhydrous][AlCl3] \underset{\underset{}{}}{2-Chlorotoluene + 4-Chlorotoluene}}\]
