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How much heat energy is necessary to raise the temperature of 5 kg of water from 20°C to 100°C?

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How much heat energy is necessary to raise the temperature of 5 kg of water from 20°C to 100°C?

How much heat energy is necessary to raise the temperature of 5 kg of water from 20°C to 100°C? [c = 1 kcal/kg°C]

Numerical
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Solution

Given: Mass (m) = 5 kg, specific heat of water (c) = 1 kcal/kg °C

Change in temperature (ΔT) = 100 − 20

= 80°C

According to the principle of heat exchange,

Energy supplied to water = Energy gained by water

= Mass of water × specific heat of water × rise in the temperature of water

Q = mc ΔT

Q = 5 × 1 × 80 

= 400 kcal

The heat energy necessary to raise the temperature of the water is 400 kcal.

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