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How much heat energy is released when 5.0 g of water at 20℃ changes into ice at 0℃? Take specific heat capacity of water = 4.2 J g-1 K-1, Specific latent heat of fusion of ice = 336 J g-1.

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Question

How much heat energy is released when 5.0 g of water at 20℃ changes into ice at 0℃? Take specific heat capacity of water = 4.2 J g-1 K-1, Specific latent heat of fusion of ice = 336 J g-1.

Numerical
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Solution

Given,

Mass (m) = 5.0 g

Specific heat capacity of water (c) = 4.2 J g-1 K-1

Specific latent heat of fusion of ice (L) = 336 J g-1

(i) Heat energy released when water lowers it's temperature from 20° C to 0° C

= m × c × change in temperature

Substituting the values in the formula we get,

Q1 = 5 × 4.2 × (20 − 0)

Q1 = 5 × 4.2 × 20

⇒ Q1 = 420 J

(ii) Heat energy released when water at 0° C changes into ice at 0° C = m × L

Substituting the values in the formula we get,

Q2 = 5 × 336 J

⇒ Q2 = 1680 J

From relation,

Q = Q1 + Q2

Q = 420 + 1680

Q = 2100

Total heat released = 2100 J

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Chapter 11: Calorimetry - EXERCISE-11 (B) [Page 281]

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Selina Physics [English] Class 10 ICSE
Chapter 11 Calorimetry
EXERCISE-11 (B) | Q 2. | Page 281

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