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Question
How is the variability in oxidation states of transition metals different from that of the non-transition metals? Illustrate with examples.
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Solution
In transition metals, the oxidation state changes from +1 to higher states by a gradual change of one. For example, in manganese it is found to be +2, +3, +4, +5, +6, +7. In non-transition metals, the change is selective and generally changes by a difference of 2. For example, the oxidation states of Sn are +2 and +4.
RELATED QUESTIONS
Why do interstitial compounds have higher melting points than corresponding pure metals?
|
`E_((M^(2+)/M)` |
Cr | Mn | Fe | Co | Ni | Cu |
| -0.91 | -1.18 | -0.44 | -0.28 | -0.25 | -0.34 |
From the given data of E0 values, answer the following questions :
(1) Why is `E_(((Cu^(2+))/(Cu)))` value exceptionally positive
(2) Why is `E_(((Mn^(2+))/(Mn)))` value is highly negative as compared to other elements
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Assertion: Separation of \[\ce{Zr}\] and \[\ce{Hf}\] is difficult.
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