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How is the variability in oxidation states of transition metals different from that of the non-transition metals? Illustrate with examples.

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प्रश्न

How is the variability in oxidation states of transition metals different from that of the non-transition metals? Illustrate with examples.

लघु उत्तरीय
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उत्तर

In transition metals, the oxidation state changes from +1 to higher states by a gradual change of one. For example, in manganese it is found to be +2, +3, +4, +5, +6, +7. In non-transition metals, the change is selective and generally changes by a difference of 2. For example, the oxidation states of Sn are +2 and +4.

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अध्याय 4: d-and ƒ-Block Elements - 'NCERT TEXT-BOOK, Exercises [पृष्ठ ५०६]

APPEARS IN

नूतन Chemistry [English] Class 12 ISC
अध्याय 4 d-and ƒ-Block Elements
'NCERT TEXT-BOOK, Exercises | Q 8.13 | पृष्ठ ५०६
एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 4 The d-block and f-block Elements
Exercises | Q 4.13 | पृष्ठ ११५

संबंधित प्रश्न

Give reasons:

Transition metals show variable oxidation states.


To what extent do the electronic configurations decide the stability of oxidation states in the first series of the transition elements? Illustrate your answer with examples.


Which one of the following ions is coloured?


Following are the transition metal ions of 3d series:

Ti4+, V2+, Mn3+, Cr3+

(Atomic numbers: Ti = 22, V = 23, Mn = 25, Cr = 24)

Answer the following:

1) Which ion is most stable in an aqueous solution and why?

2) Which ion is a strong oxidising agent and why?

3) Which ion is colourless and why?


How would you account for the following? 

Transition metals and their compounds act as catalysts.


Why do transition elements show variable oxidation states ? In 3d series (Sc to Zn), which elements shows the maximum number of oxidation state and why ?


Which among the following transition metal has the lowest melting point?


When \[\ce{KMnO4}\] solution is added to oxalic acid solution, the decolourisation is slow in the beginning but becomes instantaneous after some time because ______.


Which of the following statements is not correct?


Match the properties given in Column I with the metals given in Column II.

  Column I (Property) Column II (Metal)
(i)  An element which can show +8 oxidation state (a) \[\ce{Mn}\]
(ii)  3d block element that can show (b) \[\ce{Cr}\]
  upto +7 oxidation state (c) \[\ce{Os}\]
(iii)  3d block element with highest melting point (d) \[\ce{Fe}\]

Match the properties given in Column I with the metals given in Column II.

  Column I (Property) Column II (Metal)
(i) Element with highest second
ionisation enthalpy
(a) \[\ce{Co}\]
(ii) Element with highest
third ionisation enthalpy
(b) \[\ce{Cr}\]
(iii) \[\ce{M}\] in \[\ce{M(CO)6}\] is (c) \[\ce{Cu}\]
(iv) Element with highest heat
of atomisation
(d) \[\ce{Zn}\]
    (e) \[\ce{Ni}\]

Assertion: The highest oxidation state of osmium is +8.

Reason: Osmium is a 5d-block element.


Answer the following question:

Which element of the first transition series has lowest enthalpy of atomisation?


On strong heating AgNO3, the gases evolved are:-


The product of oxidation of I with \[\ce{MnO^{-}4}\] in alkaline medium is:-


Which of the following species has maximum magnetic momentum?


Why is the `"E"_(("V"^(3+)//"V"^(2+)))^"o"` value for vanadium comparatively low?


Consider the following standard electrode potentials (E° in volts) in aqueous solution:

Element M3+/M M+/M
Al - 1.66 +0.55
Tl + 1.26 -0.34

Based on these data, which of the following statements is correct?


The trend of which property is represented by the following graph?


Explain the use of different transition metals as catalysts.


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