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Question
From diagram given below calculate:
- velocity of P and Q
- frequency of P, when frequency of Q is 512 Hz.
Assume that both wave are traveling in same medium.
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Solution
For Q:
Wavelength (λ) = Distance between two consecutive crests
= 0.5 - 0.1 = 0.4 m
Frequency(f) = 515 Hz
Velocity(v) = λf
= 0.4 × 512 = 204.8 ms-1
Since both waves are travelling in same medium and velocity of P and Q is same i.e. 204.8 ms-1
For P:
Wavelength = λ' = 1.0 - 0.2 = 0.8 m
Velocity = v = 204.8 ms-1
Frequnecy of wave P = f' = ?
v = λ'f'
f = `"v"/(lambda') = 204.8/0.8 = 256` Hz
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