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For the following data, find the regression line of Y on X X 1 2 3 Y 2 1 6 Hence find the most likely value of y when x = 4.

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Question

For the following data, find the regression line of Y on X

X 1 2 3
Y 2 1 6

Hence find the most likely value of y when x = 4.

Sum
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Solution

X = xi Y = yi `bb("x"_"i"^2)` xi yi
1 2 1 2
2 1 4 2
3 6 9 18
6 9 14 22

From the table, we have

n = 3, ∑ xi = 6, ∑ yi = 9, `sum "x"_"i"^2 = 14`, ∑ xi yi = 22

`bar x = (sum x_i)/"n" = 6/3 = 2`

`bar y = (sum y_i)/"n" = 9/3 = 3`

Now, `"b"_"YX" = (sum"x"_"i" "y"_"i" - "n" bar "x" bar "y")/(sum "x"_"i"^2 - "n" bar"x"^2)`

`= (22 - 3xx2xx3)/(14 - 3(2)^2)`

`= (22 - 18)/(14 - 12)`

`= 4/2`

= 2

The regression equation of Y on X is,

`(y - bary) = "b"_("YX") (x - barx)`

y − 3 = 2(x − 2)

y − 3 = 2x − 4

y = 2x − 4 + 3

y = 2x − 1 is the regression equation of Y on X.   ...(1)

When x = 4, y = ?

Substituting x = 4 in equation (1)

y = 2(4) − 1

= 8 − 1

y = 7

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Types of Linear Regression
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Chapter 3: Linear Regression - Exercise 3.1 [Page 42]

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