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The following sample gives the number of hours of study (X) per day for an examination and marks (Y) obtained by 12 students. Obtain the line of regression of marks on hours of study.

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Question

The following sample gives the number of hours of study (X) per day for an examination and marks (Y) obtained by 12 students.

X 3 3 3 4 4 5 5 5 6 6 7 8
Y 45 60 55 60 75 70 80 75 90 80 75 85

Obtain the line of regression of marks on hours of study.

Sum
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Solution

X = xi Y = yi `bb("x"_"i"^2)` xi yi
3 45 9 135
3 60 9 180
3 55 9 165
4 60 16 240
4 75 16 300
5 70 25 350
5 80 25 400
5 75 25 375
6 90 36 540
6 80 36 480
7 75 49 525
8 85 64 680
59 850 319 4370

From the table, we have

n = 12, ∑ xi = 59, ∑ yi = 850, `sum "x"_"i"^2 = 319`, ∑ xi yi = 4370

`bar x = (sum x_i)/"n" = 59/12 = 4.92`

`bar y = (sum y_i)/"n" = 850/12 = 70.83`

Now, `"b"_"YX" = (sum"x"_"i" "y"_"i" - "n" bar "x" bar "y")/(sum "x"_"i"^2 - "n" bar"x"^2)`

`= (4370 - 12 xx 4.92 xx 70.83)/(319 - 12 xx (4.92)^2)`

`= (4370  -  4181.80)/(319  -  290.48)`

`= 188.2/28.52` = 6.6

Also, `"a" = bar y - "b"_"YX"  bar x`

= 70.83 - 6.6 × 4.92

= 70.83 - 32.47

= 38.36

∴ The regression equation of Y on X is,

Y = a + bYX X

∴ Y = 38.36 + 6.6 X

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Types of Linear Regression
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Chapter 3: Linear Regression - Exercise 3.1 [Page 42]

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