English

For any integer n, the value of ππ∫-ππecos2xsin3(2n+1)x dx is ______.

Advertisements
Advertisements

Question

For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is ______.

Options

  • –1

  • 0

  • 1

  • 2

MCQ
Fill in the Blanks
Advertisements

Solution

For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is 0.

Explanation:

f(x) = `e^(cos^2x) sin^3 (2n + 1)x`

f(–x) = `e^(cos^2(-x)) sin^3 (2n + 1)(-x)`

f(–x) = `-e^(cos^2x) sin^3 (2n + 1)x`

∵ f(–x) = –f(x)

So, `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` = 0

shaalaa.com
  Is there an error in this question or solution?
2023-2024 (March) Board Sample Paper

RELATED QUESTIONS

If `int_0^alpha(3x^2+2x+1)dx=14` then `alpha=`

(A) 1

(B) 2

(C) –1

(D) –2


By using the properties of the definite integral, evaluate the integral:

`int_(pi/2)^(pi/2) sin^7 x dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(2x) cos^5 xdx`


Prove that `int_0^af(x)dx=int_0^af(a-x) dx`

hence evaluate `int_0^(pi/2)sinx/(sinx+cosx) dx`


\[\int\limits_0^a 3 x^2 dx = 8,\] find the value of a.


Using properties of definite integrals, evaluate 

`int_0^(π/2)  sqrt(sin x )/ (sqrtsin x + sqrtcos x)dx`


Choose the correct alternative:

`int_(-9)^9 x^3/(4 - x^2)  "d"x` =


`int_-9^9 x^3/(4 - x^2)` dx = ______


`int_0^{pi/2} cos^2x  dx` = ______ 


`int_{pi/6}^{pi/3} sin^2x dx` = ______ 


If `int_0^"k" "dx"/(2 + 32x^2) = pi/32,` then the value of k is ______.


`int_(pi/4)^(pi/2) sqrt(1-sin 2x)  dx =` ______.


`int_0^1 "e"^(5logx) "d"x` = ______.


`int_0^(2"a") "f"("x") "dx" = int_0^"a" "f"("x") "dx" + int_0^"a" "f"("k" - "x") "dx"`, then the value of k is:


Evaluate: `int_0^(2π) (1)/(1 + e^(sin x)`dx


`int_0^1 1/(2x + 5) dx` = ______.


Let `int_0^∞ (t^4dt)/(1 + t^2)^6 = (3π)/(64k)` then k is equal to ______.


Let f be continuous periodic function with period 3, such that `int_0^3f(x)dx` = 1. Then the value of `int_-4^8f(2x)dx` is ______.


Evaluate: `int_1^3 sqrt(x + 5)/(sqrt(x + 5) + sqrt(9 - x))dx`


Evaluate the following integral:

`int_0^1 x(1 - 5)^5`dx


If `int_0^1(3x^2 + 2x+a)dx = 0,` then a = ______


Evaluate `int_0^3root3(x+4)/(root3(x+4)+root3(7-x))  dx`


Evaluate the following integral:

`int_0^1x (1 - x)^5 dx`


Evaluate the following integral:

`int_-9^9 x^3/(4-x^2)dx`


Solve the following.

`int_2^3x/((x+2)(x+3))dx`


Evaluate the following integral:

`int_0^1 x(1-x)^5 dx`


Solve.

`int_0^1e^(x^2)x^3dx`


Evaluate the following definite intergral:

`int_1^2 (3x)/(9x^2 - 1) dx`


Evaluate the following integral:

`int_0^1x(1 - x)^5dx`


Evaluate the following integral:

`int_-9^9x^3/(4-x^2)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×