English

For any integer n, the value of ππ∫-ππecos2xsin3(2n+1)x dx is ______.

Advertisements
Advertisements

Question

For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is ______.

Options

  • –1

  • 0

  • 1

  • 2

MCQ
Fill in the Blanks
Advertisements

Solution

For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is 0.

Explanation:

f(x) = `e^(cos^2x) sin^3 (2n + 1)x`

f(–x) = `e^(cos^2(-x)) sin^3 (2n + 1)(-x)`

f(–x) = `-e^(cos^2x) sin^3 (2n + 1)x`

∵ f(–x) = –f(x)

So, `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` = 0

shaalaa.com
  Is there an error in this question or solution?
2023-2024 (March) Board Sample Paper

RELATED QUESTIONS

Prove that: `int_0^(2a)f(x)dx=int_0^af(x)dx+int_0^af(2a-x)dx`


Evaluate: `int_(-a)^asqrt((a-x)/(a+x)) dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^pi log(1+ cos x) dx`


Show that `int_0^a f(x)g (x)dx = 2 int_0^a f(x) dx`  if f and g are defined as f(x) = f(a-x) and g(x) + g(a-x) = 4.


Evaluate `int e^x [(cosx - sin x)/sin^2 x]dx`


\[\int\limits_0^k \frac{1}{2 + 8 x^2} dx = \frac{\pi}{16},\] find the value of k.


Evaluate : `int _0^(pi/2) "sin"^ 2  "x"  "dx"`


Evaluate : `int  "e"^(3"x")/("e"^(3"x") + 1)` dx


`int_0^2 e^x dx` = ______.


`int_0^1 ((x^2 - 2)/(x^2 + 1))`dx = ?


`int_0^{pi/2} cos^2x  dx` = ______ 


If `int_0^"k" "dx"/(2 + 32x^2) = pi/32,` then the value of k is ______.


`int_(pi/4)^(pi/2) sqrt(1-sin 2x)  dx =` ______.


`int_(-pi/4)^(pi/4) 1/(1 - sinx) "d"x` = ______.


Find `int_0^(pi/4) sqrt(1 + sin 2x) "d"x`


Evaluate the following:

`int_(-pi/4)^(pi/4) log|sinx + cosx|"d"x`


`int_((-pi)/4)^(pi/4) "dx"/(1 + cos2x)` is equal to ______.


The value of `int_0^1 tan^-1 ((2x - 1)/(1 + x - x^2))  dx` is


The value of the integral `int_(-1)^1log_e(sqrt(1 - x) + sqrt(1 + x))dx` is equal to ______.


Let a be a positive real number such that `int_0^ae^(x-[x])dx` = 10e – 9 where [x] is the greatest integer less than or equal to x. Then, a is equal to ______.


If `β + 2int_0^1x^2e^(-x^2)dx = int_0^1e^(-x^2)dx`, then the value of β is ______.


Evaluate: `int_1^3 sqrt(x + 5)/(sqrt(x + 5) + sqrt(9 - x))dx`


The value of `int_0^(π/4) (sin 2x)dx` is ______.


Evaluate: `int_0^π x/(1 + sinx)dx`.


Evaluate : `int_-1^1 log ((2 - x)/(2 + x))dx`.


Evaluate `int_1^2(x+3)/(x(x+2))  dx`


Evaluate the following definite integral:

`int_1^3 log x  dx`


Evaluate the following integral:

`int_0^1x (1 - x)^5 dx`


Evaluate:

`int_0^6 |x + 3|dx`


The area enclosed between the graph of y = x3 and the lines x = 0, y = 1, y = 8 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×