मराठी

For any integer n, the value of ππ∫-ππecos2xsin3(2n+1)x dx is ______.

Advertisements
Advertisements

प्रश्न

For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is ______.

पर्याय

  • –1

  • 0

  • 1

  • 2

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is 0.

Explanation:

f(x) = `e^(cos^2x) sin^3 (2n + 1)x`

f(–x) = `e^(cos^2(-x)) sin^3 (2n + 1)(-x)`

f(–x) = `-e^(cos^2x) sin^3 (2n + 1)x`

∵ f(–x) = –f(x)

So, `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` = 0

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2023-2024 (March) Board Sample Paper

संबंधित प्रश्‍न

If `int_0^alpha(3x^2+2x+1)dx=14` then `alpha=`

(A) 1

(B) 2

(C) –1

(D) –2


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) sin^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`


By using the properties of the definite integral, evaluate the integral:

`int_(-5)^5 | x + 2| dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^pi (x  dx)/(1+ sin x)`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) (sin x - cos x)/(1+sinx cos x) dx`


Prove that `int_0^af(x)dx=int_0^af(a-x) dx`

hence evaluate `int_0^(pi/2)sinx/(sinx+cosx) dx`


Evaluate `int e^x [(cosx - sin x)/sin^2 x]dx`


Evaluate : `int 1/("x" [("log x")^2 + 4])  "dx"`


Evaluate `int_1^2 (sqrt(x))/(sqrt(3 - x) + sqrt(x))  "d"x`


`int_0^1 ((x^2 - 2)/(x^2 + 1))`dx = ?


The value of `int_-3^3 ("a"x^5 + "b"x^3 + "c"x + "k")"dx"`, where a, b, c, k are constants, depends only on ______.


`int_0^1 log(1/x - 1) "dx"` = ______.


`int_0^9 1/(1 + sqrtx)` dx = ______ 


Find `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x)) "d"x`


`int_("a" + "c")^("b" + "c") "f"(x) "d"x` is equal to ______.


`int_0^1 1/(2x + 5) dx` = ______.


`int_a^b f(x)dx` = ______.


If `β + 2int_0^1x^2e^(-x^2)dx = int_0^1e^(-x^2)dx`, then the value of β is ______.


Let `int ((x^6 - 4)dx)/((x^6 + 2)^(1/4).x^4) = (ℓ(x^6 + 2)^m)/x^n + C`, then `n/(ℓm)` is equal to ______.


The value of the integral `int_0^sqrt(2)([sqrt(2 - x^2)] + 2x)dx` (where [.] denotes greatest integer function) is ______.


If `lim_("n"→∞)(int_(1/("n"+1))^(1/"n") tan^-1("n"x)"d"x)/(int_(1/("n"+1))^(1/"n") sin^-1("n"x)"d"x) = "p"/"q"`, (where p and q are coprime), then (p + q) is ______.


With the usual notation `int_1^2 ([x^2] - [x]^2)dx` is equal to ______.


`int_0^(π/4) x. sec^2 x  dx` = ______.


`int_((-π)/2)^(π/2) log((2 - sinx)/(2 + sinx))` is equal to ______.


Evaluate `int_-1^1 |x^4 - x|dx`.


Solve the following.

`int_1^3 x^2 logx  dx`


 `int_-9^9 x^3/(4-x^2) dx` =______


Evaluate the following integral:

`int_0^1x(1-x)^5dx`


Why can \[\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}}\sin^{2}x\,dx\] be written as \[2\int_{0}^{\frac{\pi}{4}}\sin^{2}x\,dx\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×