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Question
Five atoms are labelled V to Z
| Atoms | Mass Number | Atomic Number |
| V | 40 | 20 |
| W | 19 | 9 |
| X | 7 | 3 |
| Y | 16 | 8 |
| Z | 14 | 7 |
- Which one of these atoms
(1) contains 7 protons;
(2) has an electronic configuration 2, 7? - Write down the formula of the compound formed by atoms X and Y.
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Solution
(i) As Z has atomic number of 7, hence it has 7 protons. Electronic configuration of 2, 7 means the atom has 2 + 7 = 9 electrons. Therefore, element W has electronic configuration 2, 7 since its atomic number is 9.
(ii) Number of electron in X is 3. Therefore, electronic configuration = (2, 1). As X will try to lose 1 electron to attain stable state, hence, X has valency [1+]
Number of electron in Y is 8. Therefore, electronic configuration = (2, 6). As Y will try to gain 2 electrons to attain stable state, hence, Y has valency [2−]
Since the valency of X is 1+ and valency of Y is 2−
Formula of the compound:
X1+ Y2−
So, we get the formula as X2Y.
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Fill in the blank.
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|
Atoms |
Mass No |
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|
A |
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|
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