Advertisements
Advertisements
Question
Find the value of energy of electron in eV in the third Bohr orbit of hydrogen atom.
(Rydberg's constant (R) = 1· 097 x 107m - 1,Planck's constant (h) =6·63x10-34 J-s,Velocity of light in air (c) = 3 x 108m/ s.)
Advertisements
Solution
R = 1.097 × 107 m-1
h = 6.63 × 10-34 J - s ,
c = 3 × 108 m/s
n = 3
e = 1.6 × 10-19 C ,
E3 = ?
E = `(-6.63 xx 10^-34 xx 1.097 xx 10^7 xx 3 xx 10^8)/(9 xx 1.6 xx 10^-19)`
`= (-6.63 xx 1.097 xx 3)/(9 xx 1.6)`
`= - ["log" (6.63) + "log" (1.097) + "log"(3) - "log"(9) - "log" (1.6)]`
`[0.8215 + 0.0402 + 0.4771 - 0.9542 - 0.2041]`
`["antilog" (0.1805)]`
= 1.515 eV
The value of energy of electron in the third bohr orbit of hydrogen atom is 1.515 eV .
APPEARS IN
RELATED QUESTIONS
The energy of photon of wavelength X is_____ .
[h = Planck’s constant, c = speed of light in vacuum]
When radiations of wavelength λ1 and λ2 are incident on certain photosensitive, such that E1 > E2 . Then Planck's constant 'h' is ......................... .
(C = Velocity of light).
The photoelectric threshold wavelength of a metal is 230 nm. Determine the maximum kinetic energy in joule and in eV of the ejects electron for the metal surface when it is exposed to a radiation of wavelength 180 nm.
[Planck’s constant : h = 6.63 * 10-34 Js, Velocity of light : C = 3 * 108 m/s.]
Write Einstein's photoelectric equation and mention which important features in photoelectric effect can be explained with the help of this equation.
The maximum kinetic energy of the photoelectrons gets doubled when the wavelength of light incident on the surface changes from λ1 to λ2. Derive the expressions for the threshold wavelength λ0 and work function for the metal surface.
A proton and a deuteron are accelerated through the same accelerating potential. Which one of the two has less momentum?
Give reasons to justify your answer.
Write the basic features of photon picture of electromagnetic radiation on which Einstein’s photoelectric equation is based.
Write Einstein’s photoelectric equation.
According to Einstein’s model, the threshold frequency for a metal having work function ϕ0 is given by _________.
According to the Einstein’s model, stopping potential Vo for a metal having work function ϕ0 is given by ______.
Radiations of two photon's energy, twice and ten times the work function of metal are incident on the metal surface successively. The ratio of maximum velocities of photoelectrons emitted in two cases is:
According to Einstein's photoelectric equation, the plot of the kinetic energy of the emitted photoelectrons from a metal Vs the frequency of the incident radiation gives as straight the whose slope:
A 200 W sodium street lamp emits yellow light of wavelength 0.6 µm. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is:
Dimensions of ‘resistance’ are same as (where h is Planck's constant and e is charge):
If the energy of photon corresponding to a wavelength of 6000 A° is 3.32 × 10−19 J, the photon energy for a wavelength of 4000 A° will be ______.
The slope of frequency of incident light and stopping potential for a given surface will be
What will be wavelength of a photon of momentum 6.6 × 10–24 kgms–1?
What is the momentum of photon of energy 3 mev in kg ms-1?
Which of the following is/are true for cathode ray
The emission of electron is possible
The wavelength of matter is independent of
Ultraviolet light is incident on metals P, Q and R, having work functions 8 eV, 2 eV and 4 eV respectively,
- Which metal has lowest threshold frequency for photoelectric effect?
- For which metal is the value of Emax minimum?
(Note: Emax is maximum kinetic energy of the emitted photoelectrons.)
How does stopping potential in photoelectric emission vary if the intensity of the incident radiation increases?
How does stopping potential in photoelectric emission vary if the frequency of incident radiation decreases?
The graphs below show the variation of the stopping potential VS with the frequency (ν) of the incident radiations for two different photosensitive materials M1 and M2.
Express work function for M1 and M2 in terms of Planck’s constant(h) and Threshold frequency and charge of the electron (e).
If the values of stopping potential for M1 and M2 are V1 and V2 respectively then show that the slope of the lines equals to `(V_1-V_2)/(V_(01)-V_(02))` for a frequency,
ν > ν02 and also ν > ν01
