Question

Einstein's photoelectric equation is:

a) `E_"max" = hlambda - varphi_0`

b) `E_"max"= (hc)/lambda  varphi_0`

c) `E_"max" = hv + varphi_0`

d) `E_"max" = (hv)/lambda + varphi_0`

Answer 1

`E_"max"= (hc)/lambda  varphi_0`

∵ `hv + phi_0 + E_"max"`