Question

Find the value of energy of electron in eV in the third Bohr orbit of hydrogen atom.

(Rydberg's constant (R) = 1· 097 x 10⁷m ^{- 1},Planck's constant (h) =6·63x10^-34 J-s,Velocity of light in air (c) = 3 x 10⁸m/ s.)

Answer 1

R = 1.097 × 10⁷ m^-1

h = 6.63 × 10^-34 J - s ,

c = 3 × 10⁸ m/s

n = 3

e = 1.6 × 10^-19 C ,

E₃ = ?

E = `(-6.63 xx 10^-34 xx 1.097 xx 10^7 xx 3 xx 10^8)/(9 xx 1.6 xx 10^-19)`

`= (-6.63 xx 1.097 xx 3)/(9 xx 1.6)`

`= - ["log" (6.63) + "log" (1.097) + "log"(3) - "log"(9) - "log" (1.6)]`

`[0.8215 + 0.0402 + 0.4771 - 0.9542 - 0.2041]`

`["antilog" (0.1805)]`

= 1.515 eV

The value of energy of electron in the third bohr orbit of hydrogen atom is 1.515 eV .