Question

Find the values of k for the following quadratic equation, so that they have two equal roots. 

2x² + kx + 3 = 0

Answer 1

2x² + kx + 3 = 0

Comparing equation with ax² + bx + c = 0, we get

a = 2, b = k and c = 3

Discriminant = b² - 4ac

= `(k)^2 - 4xx2xx3`

= k² - 24

For equal roots,

Discriminant = 0

k² - 24 = 0

k² = 24

k = `±sqrt24`

k = `±2sqrt6`