Advertisements
Advertisements
Question
Discuss the nature of the roots of the following quadratic equations : x2 – 4x – 1 = 0
Advertisements
Solution
x2 – 4x – 1 = 0
Here a = 1, b = -4, c = -1
∴ D = b2 - 4ac
= (-4)2 - 4 x 1 x (-1)
= 16 + 4
= 20
∵ D > 0
Roots are real and distinct.
APPEARS IN
RELATED QUESTIONS
Find the nature of the roots of the following quadratic equation. If the real roots exist, find them:
2x2 - 3x + 5 = 0
Determine the nature of the roots of the following quadratic equation:
`3/5x^2-2/3x+1=0`
In the following determine the set of values of k for which the given quadratic equation has real roots:
3x2 + 2x + k = 0
Choose the correct alternative answer for the following sub questions and write the correct alphabet.
What is the value of discriminant for the quadratic equation X2 – 2X – 3 = 0?
The roots of the quadratic equation 6x2 – x – 2 = 0 are:
If one root of the equation x2+ px + 12 = 0 is 4, while the equation x2 + px + q = 0 has equal roots, the value of q is:
The equation 12x2 + 4kx + 3 = 0 has real and equal roots, if:
Equation (x + 1)2 – x2 = 0 has ____________ real root(s).
Which of the following equations has the sum of its roots as 3?
Find the value of 'p' for which the quadratic equation p(x – 4)(x – 2) + (x –1)2 = 0 has real and equal roots.
