Advertisements
Advertisements
प्रश्न
Discuss the nature of the roots of the following quadratic equations : x2 – 4x – 1 = 0
Advertisements
उत्तर
x2 – 4x – 1 = 0
Here a = 1, b = -4, c = -1
∴ D = b2 - 4ac
= (-4)2 - 4 x 1 x (-1)
= 16 + 4
= 20
∵ D > 0
Roots are real and distinct.
APPEARS IN
संबंधित प्रश्न
Solve for x: `sqrt(3x^2)-2sqrt(2)x-2sqrt3=0`
Find the values of k for which the roots are real and equal in each of the following equation:
2kx2 - 40x + 25 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + 3x + k = 0
`(2)/x^2 - (5)/x + 2` = 0
Find the value of k for which the given equation has real roots:
9x2 + 3kx + 4 = 0.
Find the value of k so that sum of the roots of the quadratic equation is equal to the product of the roots:
kx2 + 6x - 3k = 0, k ≠ 0
Find the discriminant of the following equations and hence find the nature of roots: 16x2 - 40x + 25 = 0
Solve for x: `5/2 x^2 + 2/5 = 1 - 2x`.
The roots of the quadratic equation px2 – qx + r = 0 are real and equal if ______.
One root of equation 3x2 – mx + 4 = 0 is 1, the value of m is ______.
