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Find the value of a, if the distance between the points A(–3, –14) and B(a, –5) is 9 units. - Mathematics

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Question

Find the value of a, if the distance between the points A(–3, –14) and B(a, –5) is 9 units.

Sum
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Solution

Distance between two points (x1, y1) ( x2, y2) is:

d = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

Distance between A(–3, –14) and B(a, –5) is:

d = `sqrt([(a + 3)^2 + (-5 + 14)^2])` = 9

Squaring on L.H.S and R.H.S.

(a + 3)2 + 81 = 81

(a + 3)2 = 0

(a + 3)(a + 3) = 0

a + 3 = 0

a = –3

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Chapter 7: Coordinate Geometry - Exercise 7.3 [Page 83]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 7 Coordinate Geometry
Exercise 7.3 | Q 4 | Page 83

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