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Maharashtra State BoardSSC (English Medium) 10th Standard

Find distance between point A(–1, 1) and point B(5, –7): Solution: Suppose A(x1, y1) and B(x2, y2) x1 = –1, y1 = 1 and x2 = 5, y2 = – 7 Using distance formula, d(A, B) = (x2-x1)2+(y2-y1)2 ∴ d(A, B) = - Geometry Mathematics 2

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Question

Find distance between point A(–1, 1) and point B(5, –7):

Solution: Suppose A(x1, y1) and B(x2, y2)

x1 = –1, y1 = 1 and x2 = 5, y2 = – 7

Using distance formula,

d(A, B) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

∴ d(A, B) = `sqrt(square +[(-7) + square]^2`

∴ d(A, B) = `sqrt(square)`

∴ d(A, B) = `square`

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Solution

Suppose A(x1, y1) and B(x2, y2)

x1 = –1, y1 = 1 and x2 = 5, y2 = – 7

Using distance formula,

d(A, B) = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

∴ d(A, B) = `sqrt([5 - (-1)]^2 + [(-7) + -1]^2`

∴ d(A, B) = `sqrt(6^2 + (-8)^2`

∴ d(A, B) = `sqrt(36 + 64)`

∴ d(A, B) = `sqrt(100)`

∴ d(A, B) = 10 units

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Chapter 5: Co-ordinate Geometry - Q.2 (A)

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