Advertisements
Advertisements
Question
If A and B are the points (−6, 7) and (−1, −5) respectively, then the distance
2AB is equal to
Options
A. 13
B. 26
C. 169
D. 238
Advertisements
Solution
The given points are A (−6, 7) and B (−1, −5).
`therefore AB=sqrt((-6-(-1))^2+(7-(-5))2)`
`=sqrt((-6+1)^2+(7+5)^2)`
`=sqrt((-5)^2+(12)^2)`
`=sqrt(25+144)`
`=sqrt169`
`=13`
`therefore 2AB=2xx13=26`
Thus, the distance 2AB is 26 units.
The correct answer is B.
APPEARS IN
RELATED QUESTIONS
If P (2, – 1), Q(3, 4), R(–2, 3) and S(–3, –2) be four points in a plane, show that PQRS is a rhombus but not a square. Find the area of the rhombus
Find the distance between the points
(i) A(9,3) and B(15,11)
Find the distance of the following points from the origin:
(ii) B(-5,5)
Find all possible values of y for which distance between the points is 10 units.
Find the distance between the following pair of point.
T(–3, 6), R(9, –10)
The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is ______.
Prove that the points (0,3) , (4,3) and `(2, 3+2sqrt 3)` are the vertices of an equilateral triangle.
Give the relation that must exist between x and y so that (x, y) is equidistant from (6, -1) and (2, 3).
The distance between the points (0, 5) and (–5, 0) is ______.
Find the value of a, if the distance between the points A(–3, –14) and B(a, –5) is 9 units.
