Advertisements
Advertisements
प्रश्न
If A and B are the points (−6, 7) and (−1, −5) respectively, then the distance
2AB is equal to
पर्याय
A. 13
B. 26
C. 169
D. 238
Advertisements
उत्तर
The given points are A (−6, 7) and B (−1, −5).
`therefore AB=sqrt((-6-(-1))^2+(7-(-5))2)`
`=sqrt((-6+1)^2+(7+5)^2)`
`=sqrt((-5)^2+(12)^2)`
`=sqrt(25+144)`
`=sqrt169`
`=13`
`therefore 2AB=2xx13=26`
Thus, the distance 2AB is 26 units.
The correct answer is B.
APPEARS IN
संबंधित प्रश्न
If A(4, 3), B(-1, y) and C(3, 4) are the vertices of a right triangle ABC, right-angled at A, then find the value of y.
The length of a line segment is of 10 units and the coordinates of one end-point are (2, -3). If the abscissa of the other end is 10, find the ordinate of the other end.
A(–8, 0), B(0, 16) and C(0, 0) are the vertices of a triangle ABC. Point P lies on AB and Q lies on AC such that AP : PB = 3 : 5 and AQ : QC = 3 : 5. Show that : PQ = `3/8` BC.
The long and short hands of a clock are 6 cm and 4 cm long respectively. Find the sum of the distances travelled by their tips in 24 hours. (Use π = 3.14) ?
Find the value of y for which the distance between the points A (3, −1) and B (11, y) is 10 units.
Prove that the points (1 ,1),(-4 , 4) and (4 , 6) are the certices of an isosceles triangle.
Prove that the points P (0, -4), Q (6, 2), R (3, 5) and S (-3, -1) are the vertices of a rectangle PQRS.
Points A (-3, -2), B (-6, a), C (-3, -4) and D (0, -1) are the vertices of quadrilateral ABCD; find a if 'a' is negative and AB = CD.
The point A(2, 7) lies on the perpendicular bisector of line segment joining the points P(6, 5) and Q(0, – 4).
The points A(–1, –2), B(4, 3), C(2, 5) and D(–3, 0) in that order form a rectangle.
