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Question
Find the sum of: 4a2 + 5b2 – 6ab, 3ab, 6a2 – 2b2 and 4b2 – 5 ab
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Solution
4a2 + 5b2 – 6ab, 3ab, 6a2 – 2b2 and 4b2 – 5 ab
4a2 + 5b2 – 6ab + 3ab, 6a2 – 2b2 + 4b2 – 5 ab
= 4a2 + 6a2 + 5b2 - 2b2 + 4b2 - 6ab + 3ab - 5ab
= 10a2 + 9b2 - 2b2 - 11ab + 3ab
= 10a2 + 7b2 - 8ab
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