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Question
Find the sum of: abc + 2ba + 3ac + 4ca – 4ab + 2bca + 2ab – 3abc – 6ac
Sum
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Solution
Combine Like Terms
abc + 2abc − 3abc = (1 + 2 − 3) abc = 0
2ab − 4ab + 2ab = (2 − 4 + 2) ab = 0
3ac + 4ac − 6ac = (3 + 4 − 6) ac = 1ac = ac
= ac
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