Advertisements
Advertisements
Question
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
Advertisements
Solution
Let x – 1 = 0, then x = 1
Substituting value of x in f(x)
f(x) = 2x3 – 3x2 + 7x – 8
= 2(1)3 – 3(1)2 + 7(1) – 8
= 2 x 1 – 3 x 1 + 7 x 1– 8
= 2 – 3 + 7 – 8
= -2
∴ Remainder = 2..
APPEARS IN
RELATED QUESTIONS
Check whether 7 + 3x is a factor of 3x3 + 7x.
Find the remainder when x4 – 3x2 + 2x + 1 is divided by x – 1.
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
2x – 1
What number should be added to 3x3 – 5x2 + 6x so that when resulting polynomial is divided by x – 3, the remainder is 8?
Using the Remainder Theorem, factorise each of the following completely.
3x3 + 2x2 − 19x + 6
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 23x – 30
Using the remainder theorem, find the remainders obtained when x3 + (kx + 8 )x + k is divided by x + 1 and x − 2.
Hence, find k if the sum of the two remainders is 1.
When x3 + 3x2 – kx + 4 is divided by (x – 2), the remainder is k. Find the value of k.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x + `(1)/(2)`.
What number must be added to 2x3 – 7x2 + 2x so that the resulting polynomial leaves the remainder – 2 when divided by 2x – 3?
