Advertisements
Advertisements
प्रश्न
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
Advertisements
उत्तर
Let x – 1 = 0, then x = 1
Substituting value of x in f(x)
f(x) = 2x3 – 3x2 + 7x – 8
= 2(1)3 – 3(1)2 + 7(1) – 8
= 2 x 1 – 3 x 1 + 7 x 1– 8
= 2 – 3 + 7 – 8
= -2
∴ Remainder = 2..
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by `x - 1/2`
Use Remainder theorem to factorize the following polynomial:
`2x^3 + 3x^2 - 9x - 10`
Find the remainder when x3 + 3x2 – 12x + 4 is divided by x – 2.
What number should be added to 3x3 – 5x2 + 6x so that when resulting polynomial is divided by x – 3, the remainder is 8?
Find without division, the remainder in the following:
5x3 - 7x2 +3 is divided by (x-1)
Find without division, the remainder in the following :
x3 + 8x2 + 7x- 11 is divisible by (x+4)
use the rernainder theorem to find the factors of ( a-b )3 + (b-c )3 + ( c-a)3
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
Using remainder theorem, find the value of a if the division of x3 + 5x2 – ax + 6 by (x – 1) leaves the remainder 2a.
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
