Advertisements
Advertisements
प्रश्न
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
Advertisements
उत्तर
Let x – 1 = 0, then x = 1
Substituting value of x in f(x)
f(x) = 2x3 – 3x2 + 7x – 8
= 2(1)3 – 3(1)2 + 7(1) – 8
= 2 x 1 – 3 x 1 + 7 x 1– 8
= 2 – 3 + 7 – 8
= -2
∴ Remainder = 2..
APPEARS IN
संबंधित प्रश्न
Find the remainder when x4 – 3x2 + 2x + 1 is divided by x – 1.
Find the remainder when x3 + 3x2 – 12x + 4 is divided by x – 2.
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 1
The expression 2x3 + ax2 + bx – 2 leaves remainder 7 and 0 when divided by 2x – 3 and x + 2 respectively. Calculate the values of a and b.
Using the remainder theorem, find the remainders obtained when x3 + (kx + 8 )x + k is divided by x + 1 and x − 2.
Hence, find k if the sum of the two remainders is 1.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(2x3 − 2x2 + ax − a) ; (x − a)
Find the values of p and q in the polynomial f(x)= x3 - px2 + 14x -q, if it is exactly divisible by (x-1) and (x-2).
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 2x2 – 5x + 1
Check whether p(x) is a multiple of g(x) or not
p(x) = x3 – 5x2 + 4x – 3, g(x) = x – 2
The polynomial p(x) = x4 – 2x3 + 3x2 – ax + 3a – 7 when divided by x + 1 leaves the remainder 19. Find the values of a. Also find the remainder when p(x) is divided by x + 2.
