Advertisements
Advertisements
प्रश्न
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
Advertisements
उत्तर
Let 3x + 2 = 0,
then 3x = –2
⇒ x = `(-2)/(3)`
Substituting the value of x in f(x)
f(x) = 3x2 + 5x – 9
= `3(-2/3)^2 + 5(-2/3) -9`
= `3 xx (4)/(9) -5 xx (2)/(3) -9`
= `(4)/(3) - (10)/(3) -9`
= `-(6)/(3) -9`
= –2 – 9
= –11
∴ Remainder = –11.
APPEARS IN
संबंधित प्रश्न
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 1
If x3 + ax2 + bx + 6 has x – 2 as a factor and leaves a remainder 3 when divided by x – 3, find the values of a and b.
What number should be added to 3x3 – 5x2 + 6x so that when resulting polynomial is divided by x – 3, the remainder is 8?
Using the Remainder Theorem, factorise the following completely:
4x3 + 7x2 – 36x – 63
Using the remainder theorem, find the remainders obtained when x3 + (kx + 8 )x + k is divided by x + 1 and x − 2.
Hence, find k if the sum of the two remainders is 1.
When x3 + 3x2 – kx + 4 is divided by (x – 2), the remainder is k. Find the value of k.
Find the remainder (without divisions) on dividing f(x) by x – 2, where f(x) = 5x2 – 1x + 4
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
If x + 1 is a factor of 3x3 + kx2 + 7x + 4, then the value of k is
By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial: x4 + 1; x – 1
