Advertisements
Advertisements
प्रश्न
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
Advertisements
उत्तर
Let 3x + 2 = 0,
then 3x = –2
⇒ x = `(-2)/(3)`
Substituting the value of x in f(x)
f(x) = 3x2 + 5x – 9
= `3(-2/3)^2 + 5(-2/3) -9`
= `3 xx (4)/(9) -5 xx (2)/(3) -9`
= `(4)/(3) - (10)/(3) -9`
= `-(6)/(3) -9`
= –2 – 9
= –11
∴ Remainder = –11.
APPEARS IN
संबंधित प्रश्न
Check whether 7 + 3x is a factor of 3x3 + 7x.
Find the remainder when x4 + 1 is divided by x + 1.
Using the Remainder Theorem, factorise each of the following completely.
3x3 + 2x2 − 19x + 6
Using the Remainder Theorem, factorise the following completely:
4x3 + 7x2 – 36x – 63
Using the Remainder Theorem, factorise the following completely:
x3 + x2 – 4x – 4
Find the values of a and b when the polynomial f(x)= ax3 + 3x2 +bx -3 is exactly divisible by (2x+3) and leaves a remainder -3 when divided by (x+2).
When x3 + 3x2 – kx + 4 is divided by (x – 2), the remainder is k. Find the value of k.
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 2x2 – 5x + 1
When 2x3 – 9x2 + 10x – p is divided by (x + 1), the remainder is – 24.Find the value of p.
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
