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प्रश्न
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
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उत्तर
Let x – 1 = 0, then x = 1
Substituting value of x in f(x)
f(x) = 2x3 – 3x2 + 7x – 8
= 2(1)3 – 3(1)2 + 7(1) – 8
= 2 x 1 – 3 x 1 + 7 x 1– 8
= 2 – 3 + 7 – 8
= -2
∴ Remainder = 2..
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