Advertisements
Advertisements
प्रश्न
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 3x3 – 7x2 + 4x + 11
Advertisements
उत्तर
Let 2x + 1 = 0, then x =
Substituting the value of x in f(x):
f(x) = 3x3 – 7x2 + 4x + 11
= `3(-1/2)^3 -7(-1/2)^2 + 4(-1/2) + 11`
= `3(-1/8) -7(1/4) + 4(-1/2) + 11`
= `-(3)/(8) - (7)/(4) - 2 + 11`
= `(-3 - 14 - 16 + 88)/(8)`
= `(55)/(8)`
= `6(7)/(8)`
∴ Remainder = `6(7)/(8)`.
APPEARS IN
संबंधित प्रश्न
Using the Remainder and Factor Theorem, factorise the following polynomial:
`x^3 + 10x^2 - 37x + 26`
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 2
Find the value of a, if the division of ax3 + 9x2 + 4x – 10 by x + 3 leaves a remainder 5.
Use remainder theorem and find the remainder when the polynomial g(x) = x3 + x2 – 2x + 1 is divided by x – 3.
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by 2x + 1
When a polynomial f(x) is divided by (x – 1), the remainder is 5 and when it is,, divided by (x – 2), the remainder is 7. Find – the remainder when it is divided by (x – 1) (x – 2).
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 2x2 – 4x – 1; g(x) = x + 1
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 6x2 + 2x – 4, g(x) = `1 - 3/2 x`
The polynomial p(x) = x4 – 2x3 + 3x2 – ax + 3a – 7 when divided by x + 1 leaves the remainder 19. Find the values of a. Also find the remainder when p(x) is divided by x + 2.
