Advertisements
Advertisements
प्रश्न
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 3x3 – 7x2 + 4x + 11
Advertisements
उत्तर
Let 2x + 1 = 0, then x =
Substituting the value of x in f(x):
f(x) = 3x3 – 7x2 + 4x + 11
= `3(-1/2)^3 -7(-1/2)^2 + 4(-1/2) + 11`
= `3(-1/8) -7(1/4) + 4(-1/2) + 11`
= `-(3)/(8) - (7)/(4) - 2 + 11`
= `(-3 - 14 - 16 + 88)/(8)`
= `(55)/(8)`
= `6(7)/(8)`
∴ Remainder = `6(7)/(8)`.
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by 5 + 2x.
Find the remainder when x3 – ax2 + 6x – a is divided by x – a.
If x3 + ax2 + bx + 6 has x – 2 as a factor and leaves a remainder 3 when divided by x – 3, find the values of a and b.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(2x3 − 2x2 + ax − a) ; (x − a)
Find without division, the remainder in the following:
5x3 - 7x2 +3 is divided by (x-1)
Find the values of m and n when the polynomial f(x)= x3 - 2x2 + m x +n has a factor (x+2) and leaves a remainder 9 when divided by (x+1).
If on dividing 2x3 + 6x2 – (2k – 7)x + 5 by x + 3, the remainder is k – 1 then the value of k is
If x51 + 51 is divided by x + 1, then the remainder is
If the polynomials az3 + 4z2 + 3z – 4 and z3 – 4z + a leave the same remainder when divided by z – 3, find the value of a.
A polynomial in ‘x’ is divided by (x – a) and for (x – a) to be a factor of this polynomial, the remainder should be ______.
