Advertisements
Advertisements
प्रश्न
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
Advertisements
उत्तर
Let p(x) = x3 – 2mx2 + 16
Since, p(x) is divisible by (x + 2), then remainder = 0
P(–2) = 0
⇒ (–2)3 – 2m(–2)2 + 16 = 0
⇒ – 8 – 8m + 16 = 0
⇒ 8 = 8m
m = 1
Hence, the value of m is 1.
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x.
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 2
The polynomials ax3 + 3x2 – 3 and 2x3 – 5x + a, when divided by x – 4, leave the same remainder in each case. Find the value of a.
When x3 + 3x2 – mx + 4 is divided by x – 2, the remainder is m + 3. Find the value of m.
Find the values of a and b when the factors of the polynomial f(x)= ax3 + bx2 + x a are (x+3) and (2x-1). Factorize the polynomial completely.
What number should be added to polynomial f(x)= 12x3 + 16x2 - 5x - 8 so that the resulting polynomial is exactly divisible by (2x - 1) ?
Find the remainder (without divisions) on dividing f(x) by x – 2, where f(x) = 2x3 – 7x2 + 3
When x3 – 3x2 + 5x – 7 is divided by x – 2,then the remainder is
If x51 + 51 is divided by x + 1, the remainder is ______.
Check whether p(x) is a multiple of g(x) or not:
p(x) = 2x3 – 11x2 – 4x + 5, g(x) = 2x + 1
