Advertisements
Advertisements
प्रश्न
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
Advertisements
उत्तर
Let p(x) = x3 – 2mx2 + 16
Since, p(x) is divisible by (x + 2), then remainder = 0
P(–2) = 0
⇒ (–2)3 – 2m(–2)2 + 16 = 0
⇒ – 8 – 8m + 16 = 0
⇒ 8 = 8m
m = 1
Hence, the value of m is 1.
APPEARS IN
संबंधित प्रश्न
Using remainder theorem, find the value of k if on dividing 2x3 + 3x2 – kx + 5 by x – 2, leaves a remainder 7.
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 19x + 6
When x3 + 2x2 – kx + 4 is divided by x – 2, the remainder is k. Find the value of constant k.
Find without division, the remainder in the following:
5x2 - 9x + 4 is divided by (x - 2)
use the rernainder theorem to find the factors of ( a-b )3 + (b-c )3 + ( c-a)3
Use remainder theorem and find the remainder when the polynomial g(x) = x3 + x2 – 2x + 1 is divided by x – 3.
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by x + 3
Check whether p(x) is a multiple of g(x) or not:
p(x) = x3 – 5x2 + 4x – 3, g(x) = x – 2
If the polynomials az3 + 4z2 + 3z – 4 and z3 – 4z + a leave the same remainder when divided by z – 3, find the value of a.
What must be subtracted from the polynomial x3 + x2 – 2x + 1, so that the result is exactly divisible by (x – 3)?
