Advertisements
Advertisements
प्रश्न
What must be subtracted from the polynomial x3 + x2 – 2x + 1, so that the result is exactly divisible by (x – 3)?
पर्याय
– 31
– 30
30
31
Advertisements
उत्तर
31
Explanation:
On dividing x3 + x2 – 2x + 1 by (x – 3), we get
Put x = 3, then by remainder theorem
P(3) = 33 + 32 – 2 × 3 + 1
= 27 + 9 – 6 + 1
= 36 – 6 + 1
= 31
So, 31 must be subtracted in order to divide p(x) by (x – 3).
संबंधित प्रश्न
The expression 2x3 + ax2 + bx – 2 leaves remainder 7 and 0 when divided by 2x – 3 and x + 2 respectively. Calculate the values of a and b.
If (x – 2) is a factor of the expression 2x3 + ax2 + bx – 14 and when the expression is divided by (x – 3), it leaves a remainder 52, find the values of a and b.
When x3 + 3x2 – mx + 4 is divided by x – 2, the remainder is m + 3. Find the value of m.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(x2 − 7x + 9) ; (x + 1)
Find without division, the remainder in the following :
x3 + 8x2 + 7x- 11 is divisible by (x+4)
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x - 4
If on dividing 2x3 + 6x2 – (2k – 7)x + 5 by x + 3, the remainder is k – 1 then the value of k is
If x + 1 is a factor of 3x3 + kx2 + 7x + 4, then the value of k is
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 2x2 – 4x – 1; g(x) = x + 1
The remainder, when x3 – x2 + x – 1 is divided by x + 1, is ______.
