Question

By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x³ – 2x² – 4x – 1, g(x) = x + 1

Answer 1

Given, p(x) = x³ – 2x² – 4x – 1 and g(x) = x + 1

Here, zero of g(x) is –1.

When we divide p(x) by g(x) using remainder theorem, we get the remainder p(–1)

∴ p(–1) = (–1)² – 2(–1)² – 4(–1) – 1

= –1 – 2 + 4 – 1

= 4 – 4

= 0

Hence, remainder is 0.