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प्रश्न
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 2x2 – 4x – 1, g(x) = x + 1
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उत्तर
Given, p(x) = x3 – 2x2 – 4x – 1 and g(x) = x + 1
Here, zero of g(x) is –1.
When we divide p(x) by g(x) using remainder theorem, we get the remainder p(–1)
∴ p(–1) = (–1)2 – 2(–1)2 – 4(–1) – 1
= –1 – 2 + 4 – 1
= 4 – 4
= 0
Hence, remainder is 0.
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