Advertisements
Advertisements
Question
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 2x2 – 4x – 1, g(x) = x + 1
Advertisements
Solution
Given, p(x) = x3 – 2x2 – 4x – 1 and g(x) = x + 1
Here, zero of g(x) is –1.
When we divide p(x) by g(x) using remainder theorem, we get the remainder p(–1)
∴ p(–1) = (–1)2 – 2(–1)2 – 4(–1) – 1
= –1 – 2 + 4 – 1
= 4 – 4
= 0
Hence, remainder is 0.
APPEARS IN
RELATED QUESTIONS
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x + π.
Using remainder theorem, find the value of k if on dividing 2x3 + 3x2 – kx + 5 by x – 2, leaves a remainder 7.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(x2 − 7x + 9) ; (x + 1)
What number should be subtracted from x2 + x + 1 so that the resulting polynomial is exactly divisible by (x-2) ?
The polynomial f(x) = ax4 + x3 + bx2 - 4x + c has (x + 1), (x-2) and (2x - 1) as its factors. Find the values of a,b,c, and remaining factor.
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 4x2 + 5x + 3
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
(x – 2) is a factor of the expression x3 + ax2 + bx + 6. When this expression is divided by (x – 3), it leaves the remainder 3. Find the values of a and b.
Find the remainder when 3x3 – 4x2 + 7x – 5 is divided by (x + 3)
If x3 + 6x2 + kx + 6 is exactly divisible by (x + 2), then k = ?
