Advertisements
Advertisements
प्रश्न
What number must be subtracted from 2x2 – 5x so that the resulting polynomial leaves the remainder 2, when divided by 2x + 1 ?
Advertisements
उत्तर
Let a be subtracted from 2x2 – 5x,
Dividing 2x2 – 5x by 2x + 1,
`2x+1")"overline(2x^2-5x-a)"(x - 3`
2x2+x
– –
–6x – a
–6x – 3
+ +
–a + 3
Here remainder is (3 – a)
but we are given that remainder is 2.
∴ 3 – a = 2
⇒ –a = 2 – 3 = –1
⇒ a = 1
Hence 1 is to be subtracted.
APPEARS IN
संबंधित प्रश्न
Check whether 7 + 3x is a factor of 3x3 + 7x.
Find the value of a, if the division of ax3 + 9x2 + 4x – 10 by x + 3 leaves a remainder 5.
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 23x – 30
Using the Remainder Theorem, factorise the expression 3x3 + 10x2 + x – 6. Hence, solve the equation 3x3 + 10x2 + x – 6 = 0
Find the values of a and b when the polynomial f(x)= ax3 + 3x2 +bx -3 is exactly divisible by (2x+3) and leaves a remainder -3 when divided by (x+2).
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 2x2 – 5x + 1
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 4x2 + 5x + 3
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
If x25 + x24 is divided by (x + 1), the result is ______.
4x2 – kx + 5 leaves a remainder 2 when divided by x – 1. The value of k is ______.
