Advertisements
Advertisements
प्रश्न
Without actual division, prove that 2x4 – 5x3 + 2x2 – x + 2 is divisible by x2 – 3x + 2. [Hint: Factorise x2 – 3x + 2]
Advertisements
उत्तर
Let p(x) = 2x4 – 5x3 + 2x2 – x + 2 firstly, factorise x2 – 3x + 2.
Now, x2 – 3x + 2 = x2 – 2x – x + 2 ...[By splitting middle term]
= x(x – 2) – 1(x – 2) = (x – 1)(x – 2)
Hence, 0 of x2 – 3x + 2 are 1 and 2.
We have to prove that, 2x4 – 5x3 + 2x2 – x + 2 is divisible by x2 – 3x + 2 i.e., to prove that p(1) = 0 and p(2) = 0
Now, p(1) = 2(1)4 – 5(1)3 + 2(1)2 – 1 + 2
= 2 – 5 + 2 – 1 + 2
= 6 – 6
= 0
And p(2) = 2(2)4 – 5(2)3 + 2(2)2 – 2 + 2
= 2x16 – 5x8 + 2x4 + 0
= 32 – 40 + 8
= 40 – 40
= 0
Hence, p(x) is divisible by x2 – 3x + 2.
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x+1.
Using remainder theorem, find the value of k if on dividing 2x3 + 3x2 – kx + 5 by x – 2, leaves a remainder 7.
Find 'a' if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leaves the same remainder when divided by x + 3.
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 1
If x3 + ax2 + bx + 6 has x – 2 as a factor and leaves a remainder 3 when divided by x – 3, find the values of a and b.
If (x – 2) is a factor of the expression 2x3 + ax2 + bx – 14 and when the expression is divided by (x – 3), it leaves a remainder 52, find the values of a and b.
Given f(x) = ax2 + bx + 2 and g(x) = bx2 + ax + 1. If x – 2 is a factor of f(x) but leaves the remainder – 15 when it divides g(x), find the values of a and b. With these values of a and b, factorise the expression. f(x) + g(x) + 4x2 + 7x.
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by 2x + 1
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
