Advertisements
Advertisements
प्रश्न
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
विकल्प
6
– 6
– 3
0
Advertisements
उत्तर
f(x) = 2x3 – x2 – 3x + 5
g(x) = 2x + 1
Let 2x + 1 = 0,
then x = `(-1)/(2)`
Then remainder will be
`f((-1)/(2)) = 2((-1)/(2))^3 - ((-1)/(2))^2 -3((-1)/(2)) + 5`
= `2 xx (-1)/(8) - (1)/(4) + (3)/(2) + 5`
= `(-1)/(4) - (1)/(4) + (3)/(2) + 5`
= `(-1 -1 + 6 + 20)/(4)`
= `(24)/(4)`
= 6
∴ Remainder = 6.
APPEARS IN
संबंधित प्रश्न
Find the remainder when x4 – 3x2 + 2x + 1 is divided by x – 1.
If x3 + ax2 + bx + 6 has x – 2 as a factor and leaves a remainder 3 when divided by x – 3, find the values of a and b.
Find the value of ‘m’, if mx3 + 2x2 – 3 and x2 – mx + 4 leave the same remainder when each is divided by x – 2.
Find the number which should be added to x2 + x + 3 so that the resulting polynomial is completely divisible by (x + 3).
use the rernainder theorem to find the factors of ( a-b )3 + (b-c )3 + ( c-a)3
If on dividing 2x3 + 6x2 – (2k – 7)x + 5 by x + 3, the remainder is k – 1 then the value of k is
By remainder theorem, find the remainder when, p(x) is divided by g(x) where, p(x) = x3 – 3x2 + 4x + 50; g(x) = x – 3
Find the remainder when 3x3 – 4x2 + 7x – 5 is divided by (x + 3)
Without actual division, prove that 2x4 – 5x3 + 2x2 – x + 2 is divisible by x2 – 3x + 2. [Hint: Factorise x2 – 3x + 2]
If x25 + x24 is divided by (x + 1), the result is ______.
