Advertisements
Advertisements
प्रश्न
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
पर्याय
6
– 6
– 3
0
Advertisements
उत्तर
f(x) = 2x3 – x2 – 3x + 5
g(x) = 2x + 1
Let 2x + 1 = 0,
then x = `(-1)/(2)`
Then remainder will be
`f((-1)/(2)) = 2((-1)/(2))^3 - ((-1)/(2))^2 -3((-1)/(2)) + 5`
= `2 xx (-1)/(8) - (1)/(4) + (3)/(2) + 5`
= `(-1)/(4) - (1)/(4) + (3)/(2) + 5`
= `(-1 -1 + 6 + 20)/(4)`
= `(24)/(4)`
= 6
∴ Remainder = 6.
APPEARS IN
संबंधित प्रश्न
Using the Remainder and Factor Theorem, factorise the following polynomial:
`x^3 + 10x^2 - 37x + 26`
When x3 + 3x2 – mx + 4 is divided by x – 2, the remainder is m + 3. Find the value of m.
Find the value of p if the division of px3 + 9x2 + 4x - 10 by (x + 3) leaves the remainder 5.
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 2x2 – 5x + 1
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
Using remainder theorem, find the value of a if the division of x3 + 5x2 – ax + 6 by (x – 1) leaves the remainder 2a.
Find the remainder when 2x3 – 3x2 + 4x + 7 is divided by 2x + 1
What is the remainder when x2018 + 2018 is divided by x – 1
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 2x2 – 4x – 1, g(x) = x + 1
Check whether p(x) is a multiple of g(x) or not:
p(x) = x3 – 5x2 + 4x – 3, g(x) = x – 2
