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प्रश्न
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
पर्याय
6
– 6
– 3
0
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उत्तर
f(x) = 2x3 – x2 – 3x + 5
g(x) = 2x + 1
Let 2x + 1 = 0,
then x = `(-1)/(2)`
Then remainder will be
`f((-1)/(2)) = 2((-1)/(2))^3 - ((-1)/(2))^2 -3((-1)/(2)) + 5`
= `2 xx (-1)/(8) - (1)/(4) + (3)/(2) + 5`
= `(-1)/(4) - (1)/(4) + (3)/(2) + 5`
= `(-1 -1 + 6 + 20)/(4)`
= `(24)/(4)`
= 6
∴ Remainder = 6.
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