Advertisements
Advertisements
प्रश्न
Find the value of p if the division of px3 + 9x2 + 4x - 10 by (x + 3) leaves the remainder 5.
Advertisements
उत्तर
Here, P(-3) = 5
⇒ p(-3)3 + 9(-3)2 + 4(-3) - 10 = 5
⇒ -27p + 81 - 12 - 10 = 5
⇒ -27p = -54
⇒ p = 2
संबंधित प्रश्न
Find ‘a‘ if the two polynomials ax3 + 3x2 – 9 and 2x3 + 4x + a, leave the same remainder when divided by x + 3.
Using the Remainder Theorem, factorise the following completely:
4x3 + 7x2 – 36x – 63
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(2x3 − 2x2 + ax − a) ; (x − a)
What number should be added to polynomial f(x)= 12x3 + 16x2 - 5x - 8 so that the resulting polynomial is exactly divisible by (2x - 1) ?
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x + `(1)/(2)`.
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3)x – 6 leave the same remainder. Find the value of ‘p’.
Using the Remainder Theorem, factorise completely the following polynomial:
3x2 + 2x2 – 19x + 6
If x3 + 6x2 + kx + 6 is exactly divisible by (x + 2), then k = ?
Check whether p(x) is a multiple of g(x) or not:
p(x) = x3 – 5x2 + 4x – 3, g(x) = x – 2
What must be subtracted from the polynomial x3 + x2 – 2x + 1, so that the result is exactly divisible by (x – 3)?
