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Find the Value of P If the Division of Px3 + 9x2 + 4x - 10 by (X + 3) Leaves the Remainder 5. - Mathematics

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Question

Find the value of p if the division of px3 + 9x2 + 4x - 10 by (x + 3) leaves the remainder 5.

Sum
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Solution

Here, P(-3) = 5
⇒ p(-3)3 + 9(-3)2 + 4(-3) - 10 = 5
⇒ -27p + 81 - 12 - 10 = 5
⇒ -27p = -54
⇒ p = 2

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