Advertisements
Advertisements
प्रश्न
Find without division, the remainder in the following:
5x2 - 9x + 4 is divided by (x - 2)
Advertisements
उत्तर
5x2 - 9x + 4 is divided by (x - 2)
Putting x - 2 = 0, we get : x = 2
Substituting this value of x in the equation, we get 5 × 2 × 2 - 9 × 2 + 4 = 20 - 18 + 4 = 6
APPEARS IN
संबंधित प्रश्न
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 2
Using the Remainder Theorem, factorise each of the following completely.
3x3 + 2x2 − 19x + 6
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 23x – 30
If the polynomial y3 − 5y2 + 7y + m is divided by y + 2 and the remainder is 50 then find the value of m.
If ( x31 + 31) is divided by (x + 1) then find the remainder.
Using remainder theorem, find the value of m if the polynomial f(x)= x3 + 5x2 -mx +6 leaves a remainder 2m when divided by (x-1),
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x - 4
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = 4x3 – 12x2 + 14x – 3, g(x) = 2x – 1
Determine which of the following polynomials has x – 2 a factor:
4x2 + x – 2
Without actual division, prove that 2x4 – 5x3 + 2x2 – x + 2 is divisible by x2 – 3x + 2. [Hint: Factorise x2 – 3x + 2]
