Advertisements
Advertisements
प्रश्न
Find without division, the remainder in the following:
5x3 - 7x2 +3 is divided by (x-1)
Advertisements
उत्तर
5x3 - 7x2 +3 is divided by (x-1)
Putting x -1=0, we get: x = 1
Substituting this value of x in the equation, we get
5 x 1 x 1 x 1 - 7 x 1 x 1 + 3
= 5 - 7 + 3
= 1
APPEARS IN
संबंधित प्रश्न
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 1
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(54m3 + 18m2 − 27m + 5) ; (m − 3)
Find the values of a and b when the factors of the polynomial f(x)= ax3 + bx2 + x a are (x+3) and (2x-1). Factorize the polynomial completely.
What number should be added to 2x3 - 3x2 + 7x -8 so that the resulting polynomial is exactly divisible by (x-1) ?
The polynomial f(x) = ax4 + x3 + bx2 - 4x + c has (x + 1), (x-2) and (2x - 1) as its factors. Find the values of a,b,c, and remaining factor.
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 2x2 – 5x + 1
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 3x3 – 7x2 + 4x + 11
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
If x51 + 51 is divided by x + 1, then the remainder is
Without actual division, prove that 2x4 – 5x3 + 2x2 – x + 2 is divisible by x2 – 3x + 2. [Hint: Factorise x2 – 3x + 2]
