Advertisements
Advertisements
प्रश्न
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 3x3 – 7x2 + 4x + 11
Advertisements
उत्तर
Let 2x + 1 = 0, then x =
Substituting the value of x in f(x):
f(x) = 3x3 – 7x2 + 4x + 11
= `3(-1/2)^3 -7(-1/2)^2 + 4(-1/2) + 11`
= `3(-1/8) -7(1/4) + 4(-1/2) + 11`
= `-(3)/(8) - (7)/(4) - 2 + 11`
= `(-3 - 14 - 16 + 88)/(8)`
= `(55)/(8)`
= `6(7)/(8)`
∴ Remainder = `6(7)/(8)`.
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x+1.
Use the Remainder Theorem to find which of the following is a factor of 2x3 + 3x2 – 5x – 6.
x + 2
The polynomials ax3 + 3x2 – 3 and 2x3 – 5x + a, when divided by x – 4, leave the same remainder in each case. Find the value of a.
Polynomials bx2 + x + 5 and bx3 − 2x + 5 are divided by polynomial x - 3 and the remainders are m and n respectively. If m − n = 0 then find the value of b.
Find the values of p and q in the polynomial f(x)= x3 - px2 + 14x -q, if it is exactly divisible by (x-1) and (x-2).
What number should be added to 2x3 - 3x2 + 7x -8 so that the resulting polynomial is exactly divisible by (x-1) ?
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 4x2 + 5x + 3
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
(x – 2) is a factor of the expression x3 + ax2 + bx + 6. When this expression is divided by (x – 3), it leaves the remainder 3. Find the values of a and b.
The remainder, when x3 – x2 + x – 1 is divided by x + 1, is ______.
