Advertisements
Advertisements
प्रश्न
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 3x3 – 7x2 + 4x + 11
Advertisements
उत्तर
Let 2x + 1 = 0, then x =
Substituting the value of x in f(x):
f(x) = 3x3 – 7x2 + 4x + 11
= `3(-1/2)^3 -7(-1/2)^2 + 4(-1/2) + 11`
= `3(-1/8) -7(1/4) + 4(-1/2) + 11`
= `-(3)/(8) - (7)/(4) - 2 + 11`
= `(-3 - 14 - 16 + 88)/(8)`
= `(55)/(8)`
= `6(7)/(8)`
∴ Remainder = `6(7)/(8)`.
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 – ax2 + 6x – a is divided by x – a.
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 19x + 6
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 23x – 30
Find the value of ‘m’, if mx3 + 2x2 – 3 and x2 – mx + 4 leave the same remainder when each is divided by x – 2.
Find without division, the remainder in the following :
x3 + 8x2 + 7x- 11 is divisible by (x+4)
Find the value of p if the division of px3 + 9x2 + 4x - 10 by (x + 3) leaves the remainder 5.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x - 4
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3)x – 6 leave the same remainder. Find the value of ‘p’.
When x3 – 3x2 + 5x – 7 is divided by x – 2,then the remainder is
