Advertisements
Advertisements
प्रश्न
Find the remainder (without divisions) on dividing f(x) by x – 2, where f(x) = 5x2 – 1x + 4
Advertisements
उत्तर
Let x – 2 = 0, then x = 2
Substituting value of x in f(x)
f(x) = 5x2 – 7x + 4
⇒ f(2) = 5(2)2 – 7(2) + 4
⇒ f(2) = 20 - 14 + 4 = 10
Hence Reminder = 10.
APPEARS IN
संबंधित प्रश्न
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x+1.
Find the remainder when x3 + 3x2 + 3x + 1 is divided by `x - 1/2`
Using the Remainder Theorem, factorise the expression 3x3 + 10x2 + x – 6. Hence, solve the equation 3x3 + 10x2 + x – 6 = 0
The polynomials ax3 + 3x2 – 3 and 2x3 – 5x + a, when divided by x – 4, leave the same remainder in each case. Find the value of a.
If ( x31 + 31) is divided by (x + 1) then find the remainder.
Find the remainder when the polynomial f(x) = 2x4 - 6x3 + 2x2 - x + 2 is divided by x + 2.
(x – 2) is a factor of the expression x3 + ax2 + bx + 6. When this expression is divided by (x – 3), it leaves the remainder 3. Find the values of a and b.
If x + 1 is a factor of 3x3 + kx2 + 7x + 4, then the value of k is
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
If x25 + x24 is divided by (x + 1), the result is ______.
