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Question
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
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Solution
Let 3x + 2 = 0,
then 3x = –2
⇒ x = `(-2)/(3)`
Substituting the value of x in f(x)
f(x) = 3x2 + 5x – 9
= `3(-2/3)^2 + 5(-2/3) -9`
= `3 xx (4)/(9) -5 xx (2)/(3) -9`
= `(4)/(3) - (10)/(3) -9`
= `-(6)/(3) -9`
= –2 – 9
= –11
∴ Remainder = –11.
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