Advertisements
Advertisements
प्रश्न
Find without division, the remainder in the following:
8x2 - 2x + 1 is divided by (2x+ 1)
Advertisements
उत्तर
8x2 - 2x + 1 is divided by (2x+ 1)
Putting 2x + 1 = 0, we get : x=-`1/2`
Substituting this value of x in the equation, we get
`8 xx (-1/2) xx (-1/2) - 2 xx (-1/2) + 1`
= 2 + 1 + 1
= 4
APPEARS IN
संबंधित प्रश्न
Find the remainder when x4 + 1 is divided by x + 1.
If x3 + ax2 + bx + 6 has x – 2 as a factor and leaves a remainder 3 when divided by x – 3, find the values of a and b.
Find the value of ‘m’, if mx3 + 2x2 – 3 and x2 – mx + 4 leave the same remainder when each is divided by x – 2.
Using the remainder theorem, find the remainders obtained when x3 + (kx + 8 )x + k is divided by x + 1 and x − 2.
Hence, find k if the sum of the two remainders is 1.
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(54m3 + 18m2 − 27m + 5) ; (m − 3)
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 4x2 + 5x + 3
Using remainder theorem, find the value of a if the division of x3 + 5x2 – ax + 6 by (x – 1) leaves the remainder 2a.
When x3 – 3x2 + 5x – 7 is divided by x – 2,then the remainder is
When 2x3 – x2 – 3x + 5 is divided by 2x + 1, then the remainder is
A polynomial in ‘x’ is divided by (x – a) and for (x – a) to be a factor of this polynomial, the remainder should be ______.
