Advertisements
Advertisements
प्रश्न
Find without division, the remainder in the following:
8x2 - 2x + 1 is divided by (2x+ 1)
Advertisements
उत्तर
8x2 - 2x + 1 is divided by (2x+ 1)
Putting 2x + 1 = 0, we get : x=-`1/2`
Substituting this value of x in the equation, we get
`8 xx (-1/2) xx (-1/2) - 2 xx (-1/2) + 1`
= 2 + 1 + 1
= 4
APPEARS IN
संबंधित प्रश्न
Use the Remainder Theorem to factorise the following expression:]
`2x^3 + x^2 - 13x + 6`
Find the remainder when x4 + 1 is divided by x + 1.
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 23x – 30
Find without division, the remainder in the following:
5x2 - 9x + 4 is divided by (x - 2)
The polynomial f(x) = ax4 + x3 + bx2 - 4x + c has (x + 1), (x-2) and (2x - 1) as its factors. Find the values of a,b,c, and remaining factor.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x + 2
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x + `(1)/(2)`.
When 2x3 – 9x2 + 10x – p is divided by (x + 1), the remainder is – 24.Find the value of p.
If x51 + 51 is divided by x + 1, then the remainder is
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 3x2 + 4x + 50, g(x) = x – 3
