Advertisements
Advertisements
Question
Find without division, the remainder in the following:
8x2 - 2x + 1 is divided by (2x+ 1)
Advertisements
Solution
8x2 - 2x + 1 is divided by (2x+ 1)
Putting 2x + 1 = 0, we get : x=-`1/2`
Substituting this value of x in the equation, we get
`8 xx (-1/2) xx (-1/2) - 2 xx (-1/2) + 1`
= 2 + 1 + 1
= 4
APPEARS IN
RELATED QUESTIONS
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x.
Find the remainder when x3 – ax2 + 6x – a is divided by x – a.
Find the remainder when x4 + 1 is divided by x + 1.
Find without division, the remainder in the following:
5x2 - 9x + 4 is divided by (x - 2)
Use remainder theorem and find the remainder when the polynomial g(x) = x3 + x2 – 2x + 1 is divided by x – 3.
When x3 + 3x2 – kx + 4 is divided by (x – 2), the remainder is k. Find the value of k.
Find the value of p if the division of px3 + 9x2 + 4x - 10 by (x + 3) leaves the remainder 5.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x - 4
Find the remainder (without division) on dividing 3x2 + 5x – 9 by (3x + 2)
What number must be added to 2x3 – 7x2 + 2x so that the resulting polynomial leaves the remainder – 2 when divided by 2x – 3?
