Advertisements
Advertisements
Question
Find without division, the remainder in the following:
8x2 - 2x + 1 is divided by (2x+ 1)
Advertisements
Solution
8x2 - 2x + 1 is divided by (2x+ 1)
Putting 2x + 1 = 0, we get : x=-`1/2`
Substituting this value of x in the equation, we get
`8 xx (-1/2) xx (-1/2) - 2 xx (-1/2) + 1`
= 2 + 1 + 1
= 4
APPEARS IN
RELATED QUESTIONS
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x+1.
Find the remainder when x3 + 3x2 + 3x + 1 is divided by x + π.
Find the remainder when x4 + 1 is divided by x + 1.
Using the Remainder Theorem, factorise the following completely:
2x3 + x2 – 13x + 6
Divide the first polynomial by the second polynomial and find the remainder using remainder theorem.
(x2 − 7x + 9) ; (x + 1)
Find without division, the remainder in the following:
5x2 - 9x + 4 is divided by (x - 2)
Find the values of a and b when the polynomials f(x)= 2x2 -5x +a and g(x)= 2x2 + 5x +b both have a factor (2x+1).
The polynomial f(x) = ax4 + x3 + bx2 - 4x + c has (x + 1), (x-2) and (2x - 1) as its factors. Find the values of a,b,c, and remaining factor.
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
Without actual division, prove that 2x4 – 5x3 + 2x2 – x + 2 is divisible by x2 – 3x + 2. [Hint: Factorise x2 – 3x + 2]
