Advertisements
Advertisements
Question
By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = x3 – 6x2 + 2x – 4, g(x) = `1 - 3/2 x`
Advertisements
Solution
Given, p(x) = x3 – 6x2 + 2x – 4 and g(x) = `1 - 3/2 x`
Here, zero of g(x) is `2/3`.
When we divide p(x) by g(x) using remainder theorem, we get the remainder `p(2/3)`.
∵ `p(2/3) = (2/3)^3 - 6(2/3)^2 + 2(2/3) - 4`
= `8/27 - 6 xx 4/9 + 2 xx 2/3 - 4`
= `8/27 - 24/9 + 4/3 - 4`
= `(8 - 72 + 36 - 108)/27`
= `(-136)/27`
Hence, remainder is `(-136)/27`.
APPEARS IN
RELATED QUESTIONS
Using the Remainder Theorem, factorise the following completely:
3x3 + 2x2 – 19x + 6
What number should be subtracted from x3 + 3x2 – 8x + 14 so that on dividing it by x – 2, the remainder is 10?
Using the Remainder Theorem, factorise the following completely:
2x3 + x2 – 13x + 6
Using the Remainder Theorem, factorise the following completely:
x3 + x2 – 4x – 4
Polynomials bx2 + x + 5 and bx3 − 2x + 5 are divided by polynomial x - 3 and the remainders are m and n respectively. If m − n = 0 then find the value of b.
Find the remainder (without division) on dividing f(x) by (2x + 1) where f(x) = 3x3 – 7x2 + 4x + 11
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
If on dividing 4x2 – 3kx + 5 by x + 2, the remainder is – 3 then the value of k is
When a polynomial f(x) is divided by (x – 1), the remainder is 5 and when it is,, divided by (x – 2), the remainder is 7. Find – the remainder when it is divided by (x – 1) (x – 2).
If x25 + x24 is divided by (x + 1), the result is ______.
